(x-1)(x^2+2x-3)=0

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Solution for (x-1)(x^2+2x-3)=0 equation:


Simplifying
(x + -1)(x2 + 2x + -3) = 0

Reorder the terms:
(-1 + x)(x2 + 2x + -3) = 0

Reorder the terms:
(-1 + x)(-3 + 2x + x2) = 0

Multiply (-1 + x) * (-3 + 2x + x2)
(-1(-3 + 2x + x2) + x(-3 + 2x + x2)) = 0
((-3 * -1 + 2x * -1 + x2 * -1) + x(-3 + 2x + x2)) = 0
((3 + -2x + -1x2) + x(-3 + 2x + x2)) = 0
(3 + -2x + -1x2 + (-3 * x + 2x * x + x2 * x)) = 0
(3 + -2x + -1x2 + (-3x + 2x2 + x3)) = 0

Reorder the terms:
(3 + -2x + -3x + -1x2 + 2x2 + x3) = 0

Combine like terms: -2x + -3x = -5x
(3 + -5x + -1x2 + 2x2 + x3) = 0

Combine like terms: -1x2 + 2x2 = 1x2
(3 + -5x + 1x2 + x3) = 0

Solving
3 + -5x + 1x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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